How many three digit natural numbers are divisible by 7 ? (2024)

FAQs

How many three digit natural numbers are divisible by 7 ? ›

Hence, there are 128 three-digit numbers divisible by 7. Find how many three digit natural numbers are divisible by 5.

Hence, 128 three digit numbers are divisible by 7 .

There are 14 numbers between 1 and 100 that can be divided by 7 precisely. 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91 and 98 are the numbers.

Hence, the sum of three-digit number divisible by 7 is 70336.

Originally Answered: All three digit numbers are different and are divisible by 7. If they are reversed, they are also divisible by 7. How many such numbers are there? There are 16 such numbers: 161, 168, 252, 259, 343, 434, 525, 595, 616, 686, 700, 707, 770, 777, 868 & 959.

Solution. Three digit natural numbers which are multiples of 7 are 105, 112, 119,…, 994.

The list of two-digit numbers divisible by seven consists of: 14, 21, 28, 35…… 98 which comprise the A.P. So the total 2 digit number divided by 7 is 13.

As a result, 128 three-digit numbers can be divided by 7. n = ? Therefore, 128 three-digit numbers are divisible by 7.

As there is no remainder left, we can say that 994 is the largest three-digit number that can be exactly divided by 7.

Hence, there are 900 three-digit numbers in total.

How to find smallest 3 digit number divisible by 7? ›

Hence, the least 3 digit number divisible by 7 is 105. Note: You might have thought that why we chose 105 as a three digit number because we have asked to find the least three digit number which is divisible by 7 and after 100, the least three digit number divisible by 7 is 105.

Thus, the sum of all three digit natural numbers which are multiples of 7 is 70336.

To be divisible by both 3 and 7, a number must be divisible by 21 (their product). There are 80 integer numbers between 20 and 100, and only 4 of them satisfy the given condition. These numbers are 21, 42, 63, and 84.

Hence, there are 128 three-digit numbers divisible by 7.

So in total there are 225+26+1=252 three-digit integers with a seven as a digit.

∴ Between 3 and 200, 28 numbers are divisible by 7.

Hence, 180 three digit natural numbers are divisible by 5.

2 when divided by 7. Lowest three digit number fulfilling this condition is 100 and largest is 996. In between are (996–100)/7–1=127. Total numbers are thus 129.

n = 996 − 102 6 + 1 = 894 6 + 1 = 149 + 1 = 150 There are 150 three-digit numbers divisible by 6.